Abstract
We obtain three finite generalizations of Gauss's square exponent identity. For example, we prove that, for any non-negative integer $m$, \[ \sum _{k=-m}^{m}(-1)^k \left [{3m-k+1}\atop {m+k}\right ] (-q;q)_{m-k}q^{k^2}=1, \] where \[ \left [{\vphantom {3}n}\atop {\vphantom {k}m}\right ] =\prod _{k=1}^m\frac {1-q^{n-k+1}}{1-q^k} \quad \mbox {and}\quad (a;q)_n=\prod _{k=0}^{n-1}(1-aq^k). \] These identities reduce to Gauss's famous identity $$\sum _{k=-\infty }^{\infty }(-1)^kq^{k^2}=\frac {(q;q)_{\infty }}{(-q;q)_{\infty }}$$ by letting $m\to \infty $.
Citation
Ji-Cai Liu. "Some finite generalizations of Gauss's square exponent identity." Rocky Mountain J. Math. 47 (8) 2723 - 2730, 2017. https://doi.org/10.1216/RMJ-2017-47-8-2723
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