Abstract
We prove that there exists a nowhere weakly symmetric function $f: \mathbb{R} \rightarrow \mathbb{R}$ that is everywhere weakly symmetrically continuous and everywhere weakly continuous. Existence of a nowhere weakly symmetrically continuous function $f: \mathbb{R} \rightarrow \mathbb{R}$ that is everywhere weakly symmetric remains open.
Citation
Kandasamy Muthuvel. "Weakly Symmetric Functions and Weakly Symmetrically Continuous Functions." Real Anal. Exchange 40 (2) 455 - 458, 2015.
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