Abstract
We show that a symplectic isotopy that is a $C^0$ limit of Hamiltonian isotopies is itself Hamiltonian if the corresponding sequence of generating Hamiltonians converge in $L^{(1,\infty)}$ topology.
Citation
Sobhan Seyfaddini. "A note on $C^0$ rigidity of Hamiltonian isotopies." J. Symplectic Geom. 11 (3) 489 - 496, September 2013.
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