Open Access
April, 1969 Some First Passage Problems for $S_n/n^{\frac{1}{2} 1}$
R. A. Olshen, D. O. Siegmund
Ann. Math. Statist. 40(2): 648-652 (April, 1969). DOI: 10.1214/aoms/1177697733

Abstract

Let $x_1, x_2, \cdots$ be independent random variables with mean 0 and variance 1. Let $s_n = x_1 + \cdots + x_n, n \geqq 1$, and for each $c > 0$ define \begin{align*}\tau_1 &= \tau_1(c) = \text{first} n \geqq 1 \text{for which} s_n > cn^{\frac{1}{2}} \\ &= \infty \text{if} s_n \leqq cn^{\frac{1}{2}} \text{for all} n, \\ \end{align*} and \begin{align*}\tau_2 = \tau_2(c) &= \text{first} n \geqq 1 \text{for which} |s_n| > cn^{\frac{1}{2}} \\ &= \infty \text{if} |s_n| \leqq cn^{\frac{1}{2}} \text{for all} n. \\ \end{align*} The stopping times $\tau_1$ and $\tau_2$ have received considerable attention recently (see, for example, [1], [2], [3], [6], and [8]), and naturally there has arisen the question as to whether $P\{\tau_k < \infty\} = 1, k = 1, 2$. One contribution of this note is (1) THEOREM. If $s_n/n^{\frac{1}{2}}$ does not tend in probability to 0, then for each $c > 0, P\{\tau_2 < \infty\} = 1$. We show by examples that (1) is no longer true with $\tau_2$ replaced by $\tau_1$. The final section contains two remarks bearing on the converse to (1).

Citation

Download Citation

R. A. Olshen. D. O. Siegmund. "Some First Passage Problems for $S_n/n^{\frac{1}{2} 1}$." Ann. Math. Statist. 40 (2) 648 - 652, April, 1969. https://doi.org/10.1214/aoms/1177697733

Information

Published: April, 1969
First available in Project Euclid: 27 April 2007

zbMATH: 0172.21304
MathSciNet: MR239694
Digital Object Identifier: 10.1214/aoms/1177697733

Rights: Copyright © 1969 Institute of Mathematical Statistics

Vol.40 • No. 2 • April, 1969
Back to Top