Abstract
In this paper a solution of the following difference equation$\ $was investigated \begin{equation*} x_{n+1}=\frac{x_{n-(5k+9)}}{1+x_{n-4}x_{n-9}...x_{n-(5k+4)}},\ n=0,1,2,... \end{equation*} where $x_{-(5k+9)},x_{-(5k+8)},...,x_{-1},x_{0}\in (0,\infty ).$
Citation
Da˘gistan Simsek. Cengiz Cinar. Ibrahim Yalcinkaya. "ON THE RECURSIVE SEQUENCE $x_{n+1}=\frac{x_{n-(5k+9)}}{1+x_{n-4}x_{n-9}...x_{n-(5k+4)}}$." Taiwanese J. Math. 12 (5) 1087 - 1099, 2008. https://doi.org/10.11650/twjm/1500574249
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