Abstract
In the paper [2] we have shown that in the case of a separable Banach algebra $A$ the necessary and sufficient condition in order that a closed ideal $I\subset A$ has a dense subideal is that $I$ is not finitely (algebraically) generated. We conjectured that this result is true in the general case. In this paper we give an example showing that this conjecture fails to be true.
Citation
Wiesław Żelazko. "Concerning dense subideals in commutative Banach algebras." Funct. Approx. Comment. Math. 48 (1) 113 - 115, March 2013. https://doi.org/10.7169/facm/2013.48.1.8
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