Abstract
The following conjecture is studied. Let $G$ be a simple nonabelian group. If $H$ is any group which has the same set of character degrees as $G$, then $H \cong G \times A$, where $A$ is abelian. In the present paper this is proved if $G$ is a Suzuki group on some $SL(2,2^{f})$.
Citation
Bertram Huppert. "Some simple groups which are determined by the set of their character degrees I." Illinois J. Math. 44 (4) 828 - 842, Winter 2000. https://doi.org/10.1215/ijm/1255984694
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