Some Conditions Under Which Two Random Variables are Equal Almost Surely and a Simple Proof of a Theorem of Chung and Fuchs
Abstract
Let $(X, Y)$ be an ordered pair of real-valued random variables. Say that $(X, Y)$ is fair if $E(Y \mid X) = X$ a.s. It is shown, for example, that if $X$ has a finite mean and the pair $(X, Y)$ is fair, then $X$ and $Y$ cannot be stochastically ordered unless $X = Y$ a.s. The conclusion is in general false, if $X$ does not have a mean. On the other hand, if $X$ is independent of the increment $Y - X$, the preceding statement remains in force without any moment restrictions on $X$. The last assertion, combined with a gambling idea of Dubins and Savage, yields a simple proof of a theorem of Chung and Fuchs on the upper limit of a random walk with mean zero.
Permanent link to this document: http://projecteuclid.org/euclid.aoms/1177693163
JSTOR: links.jstor.org
Digital Object Identifier: doi:10.1214/aoms/1177693163
Mathematical Reviews number (MathSciNet): MR346898
Zentralblatt MATH identifier: 0239.60004
The Annals of Mathematical Statistics